x^2-10+37=2x+5

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Solution for x^2-10+37=2x+5 equation:


Simplifying
x2 + -10 + 37 = 2x + 5

Reorder the terms:
-10 + 37 + x2 = 2x + 5

Combine like terms: -10 + 37 = 27
27 + x2 = 2x + 5

Reorder the terms:
27 + x2 = 5 + 2x

Solving
27 + x2 = 5 + 2x

Solving for variable 'x'.

Reorder the terms:
27 + -5 + -2x + x2 = 5 + 2x + -5 + -2x

Combine like terms: 27 + -5 = 22
22 + -2x + x2 = 5 + 2x + -5 + -2x

Reorder the terms:
22 + -2x + x2 = 5 + -5 + 2x + -2x

Combine like terms: 5 + -5 = 0
22 + -2x + x2 = 0 + 2x + -2x
22 + -2x + x2 = 2x + -2x

Combine like terms: 2x + -2x = 0
22 + -2x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-22' to each side of the equation.
22 + -2x + -22 + x2 = 0 + -22

Reorder the terms:
22 + -22 + -2x + x2 = 0 + -22

Combine like terms: 22 + -22 = 0
0 + -2x + x2 = 0 + -22
-2x + x2 = 0 + -22

Combine like terms: 0 + -22 = -22
-2x + x2 = -22

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -22 + 1

Reorder the terms:
1 + -2x + x2 = -22 + 1

Combine like terms: -22 + 1 = -21
1 + -2x + x2 = -21

Factor a perfect square on the left side:
(x + -1)(x + -1) = -21

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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